题解
- 倒着单点更新
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using namespace std;
const int N=2e5+7;
typedef pair<int,int> s;
s q[N];
int tr[N<<2],ans[N],n;
inline void build(int o,int l,int r){
tr[o]=r-l+1;
if(l==r)return ;
int mid=l+r>>1;
build(lson);
build(rson);
}
inline void update(int o,int l,int r,int x,int p){
if(l==r){ans[l]=p;tr[o]=0;return ;}
int mid=l+r>>1;
if(x<=tr[o<<1])update(lson,x,p);
else update(rson,x-tr[o<<1],p);
tr[o]-=1;
}
int main(){
while(~scanf("%d",&n)){
int m=n+1;
build(1,1,m);
rep(i,1,n)scanf("%d%d",&q[i].first,&q[i].second);
repd(i,n,1)update(1,1,m,q[i].first+1,q[i].second);
rep(i,1,n)printf("%d ",ans[i]);
puts("");
}
return 0;
}