lg2922[水]

链接:lg2922[水]

题解

  • 简单Trie树,匹配路上的所有结束字符串都要加上,经过最后一个位置的字符串也要加上注意计算顺序就好…
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cmath>
#include<cstring>
#include<algorithm>
#define rep(i,x,y) for(register int i=x;i<=y;++i)
#define repd(i,x,y) for(register int i=x;i>=y;--i)
#define long long
using namespace std;
const int N=5e5+7;
int tr[N<<2][2],nm[N],sum[N<<2],n,m,cnt=1,end[N];
inline void add(int *a,int len){
int p=1;
rep(i,1,len){
if(!tr[p][a[i]])tr[p][a[i]]=++cnt;
sum[tr[p][a[i]]]++;p=tr[p][a[i]];
}
end[p]++;
}
inline int query(int *a,int len){
int p=1,ans=0;
rep(i,1,len){
if(!tr[p][a[i]])return ans;
p=tr[p][a[i]];
if(p)ans+=end[p];
}
return ans+sum[p]-end[p];
}
int main(){
//freopen("1.in","r",stdin);
//freopen("1.out","w",stdout);
scanf("%d%d",&n,&m);
rep(i,1,n){
int x;scanf("%d",&x);
rep(j,1,x)scanf("%d",&nm[j]);
add(nm,x);
}
rep(i,1,m){
int x;scanf("%d",&x);
rep(j,1,x)scanf("%d",&nm[j]);
printf("%d\n",query(nm,x));
}
return 0;
}